x
1
= 1, x
2
= 2, x
3
= 3, y
1
= 4, y
2
= 5 and y
3
= 6. Find:
Σ
3
i = 2
x
2
i
+ y
i
3
And:
Π
2
i = 1
(x
i
+ y
i
)
2